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PHP. Руководство по PHP. 2005

mysqli_insert_id

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mysqli_insert_id

(PHP 5)mysqli_insert_id

(no version information, might be only in CVS)mysqli->insert_id -- Returns the auto generated id used in the last query

Description

Procedural style:int mysqli_insert_id (mysqli link)

Object oriented style (property):class mysqli {

int insert_id

}

The mysqli_insert_id() function returns the ID generated

by a query on a table with a column having the AUTO_INCREMENT attribute. If

the last query wasn't an INSERT or UPDATE statement or if the modified table

does not have a column with the AUTO_INCREMENT attribute, this function will

return zero.

Замечание:

Performing an INSERT or UPDATE statement using the LAST_INSERT_ID()

function will also modify the value returned by the

mysqli_insert_id() function.

Возвращаемые значения

The value of the AUTO_INCREMENT field that was updated

by the previous query. Returns zero if there was no previous query on the

connection or if the query did not update an AUTO_INCREMENT

value.

Замечание:

If the number is greater than maximal int value, mysqli_insert_id()

will return a string.

Примеры

Пример 1. Object oriented style

<?php

$mysqli = new mysqli("localhost", "my_user", "my_password", "world");

/* check connection */

if (mysqli_connect_errno()){

printf("Connect failed: %s\n", mysqli_connect_error());

exit();

}

$mysqli->query("CREATE TABLE myCity LIKE City");

$query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";

$mysqli->query($query);

printf ("New Record has id %d.\n", $mysqli->insert_id);

/* drop table */

$mysqli->query("DROP TABLE myCity");

/* close connection */

$mysqli->close();

?>

Пример 2. Procedural style

<?php

$link = mysqli_connect("localhost", "my_user", "my_password", "world");

/* check connection */

if (mysqli_connect_errno()){

printf("Connect failed: %s\n", mysqli_connect_error());

exit();

}

mysqli_query($link, "CREATE TABLE myCity LIKE City");

$query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";

mysqli_query($link, $query);

printf ("New Record has id %d.\n", mysqli_insert_id($link));

/* drop table */

mysqli_query($link, "DROP TABLE myCity");

/* close connection */

mysqli_close($link);

?>

Результат выполнения данного примера:

New Record has id 1.

Пред.

Начало

След.

mysqli_init

Уровень выше

mysqli_kill

Отвечу на любые вопросы. С уважением, Дмитрий Владимирович.

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